3.854x^2+5.092x+1.44=0

Solution for 3.854x^2+5.092x+1.44=0 equation:

3.854x^2+5.092x+1.44=0

a = 3.854; b = 5.092; c = +1.44;
Δ = b2-4ac
Δ = 5.0922-4·3.854·1.44
Δ = 3.729424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.092)-\sqrt{3.729424}}{2*3.854}=\frac{-5.092-\sqrt{3.729424}}{7.708}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.092)+\sqrt{3.729424}}{2*3.854}=\frac{-5.092+\sqrt{3.729424}}{7.708}
$